Question

СРОЧНО!!!!!!!!!!! помогите решить

Answer 1

Ответ:

$\sqrt{16x} + \sqrt{100x } - \sqrt{81x} = 4 \sqrt{x} + 10 \sqrt{x} - 9 \sqrt{x} = 5 \sqrt{x} \\ \sqrt{20 } - \sqrt{125} + \sqrt{405} = \sqrt{4 \times 5} - \sqrt{25 \times 5} + \sqrt{81 \times 5} = 2 \sqrt{5} - 5 \sqrt{5} + 9 \sqrt{5} = 6 \sqrt{5} \\ 4 \sqrt{27x} - 5 \sqrt{48x} + \frac{1}{3} \sqrt{192x} = 4 \sqrt{3 \times 9x} - 5 \sqrt{3 \times 16x} + \frac{1}{3} \sqrt{3 \times 64x} = 4 \times 3 \sqrt{3x} - 5 \times 4 \sqrt{3x} + \frac{1}{3} \times 8 \sqrt{3x} = 12 \sqrt{3x} - 20 \sqrt{3x} + 2 \frac{2}{3} \sqrt{3x} = - 5 \frac{1}{3} \sqrt{3x}$

$7x \sqrt{49 {x}^{3} {y}^{5} } + 3 {x}^{2} y \sqrt{64 {y}^{3} } - 5 \sqrt{36 {x}^{5} {y}^{5} } = 7x \times 7x {y}^{2} \sqrt{xy} + 3 {x}^{2} y \times 8y \sqrt{y} - 5 \times 6 {x}^{2} {y}^{2} \sqrt{xy} = 49 {x}^{2} {y}^{2} \sqrt{xy} + 24 {x}^{2} {y}^{2} \sqrt{y} - 30 {x}^{2} {y}^{2} \sqrt{xy} = {x}^{2} {y}^{2} (49 \sqrt{xy} + 24 \sqrt{y} - 30 \sqrt{xy} ) = {x}^{2} {y}^{2} (19 \sqrt{xy} + 24 \sqrt{y} )$