Question

решите задание даю 30 балов​

Answer 1

Решим уравнение методом замены :

$\displaystyle\bf\\100x^{-2} -20x^{-1} =-1\\\\\\x^{-1} =m \ \ , \ \ x\neq 0\\\\\\100m^{2} -20m+1=0\\\\\\(10m-1)^{2} =0\\\\\\10m-1=0\\\\\\10m=1\\\\m=\frac{1}{10} \\\\\\x^{-1} =\frac{1}{10} \\\\\\\frac{1}{x} =\frac{1}{10} \\\\\\\boxed{x=10}\\\\\\\boxed{100y^{2} -20y+1=0}$