Question

помогите пожалуйста ​

Answer 1

Ответ:

$\displaystyle \binom{x;y}{2;-3}$

Объяснение:

$\displaystyle \left \{ {{\frac{x+7^{(7}}{3} +\frac{y-4^{(3}}{7}=2^{(21} ,} \atop {\frac{x-4^{(2}}{2} +\frac{y+11}{4}=1^{(4}; }} \right. \Leftrightarrow \left \{ {{7x+49+3y-12=42,} \atop {2x-8+y+11=4;}} \right. \Leftrightarrow \left \{ {{7x+3y=5,} \atop {y=-2x+1;}} \right. \Leftrightarrow \left \{ {{7x+3*(-2x+1)=5,} \atop {y=-2x+1;}} \right. \Leftrightarrow\left \{ {{7x-6x+3=5,} \atop {y=-2x+1;}} \right. \Leftrightarrow$

$\displaystyle \Leftrightarrow \left \{ {{x=2,} \atop {y=-2*2+1;}} \right. \Leftrightarrow\left \{ {{x=2,} \atop {y=-3}} \right. \\otvet:\binom{x;y}{2;-3}$