Question

Аналитически найдите координаты точки пересечения графиков функций y= -14x+32 и -10x-9

Answer 1

$\displaystyle\bf\\y=-14x+32 \ \ \ ; \ \ \ y=-10x-9\\\\-14x+32=-10x-9\\\\-14x+10x=-9-32\\\\-4x=-41\\\\x=10,25\\\\y=-10\cdot 10,25-9=-102,5-9=-111,5\\\\Otvet: \ \Big(10,25 \ \ ; \ \ -111,5\Big)$