Question

розв'яжіть систему рівнянь x+1=5(y+2) 3(2x-5)-4(3y-4)=19

Answer 1

Ответ:

$(x,y)=(18,-\frac{309}{151} )$

Объяснение:

$x+1=5(y+2)*3(2x-5)-4(3y-4)=19\\\left \{ {{x+1=19} \atop {5(y+2)*3(2x-5)-4(3y-4)=19}} \right. \\\left \{ {{x=18} \atop {5(y+2)*3(2*18-5)-4(3y-4)=19}} \right. \\\\y=-\frac{309}{151} \\\\18+1=5(-\frac{309}{151} +2)*3(2x-5)-4(3*(-\frac{309}{151}) -4)=19\\19=19=19\\(x,y)=(18,-\frac{309}{151})$