Question

8) Сравни
$\frac{3}{18} + \frac{7}{18} ? \frac{12}{18} - \frac{6}{18}$
$\frac{3}{36} + \frac{8}{36} ?( \frac{9}{36} - \frac{4}{36}) + \frac{7}{36}$
помогите пожалуйста​

Answer 1

$\displaystyle 1)\frac{3}{18}+\frac{7}{18}=\frac{3+7}{18}=\frac{10}{18}=\frac{5}{9}\\ \\\frac{12}{18}-\frac{6}{18}=\frac{12-6}{18}=\frac{6}{18}=\frac{1}{3}\\\\ \frac{3}{18}+ \frac{7}{18} > \frac{12}{18}-\frac{6}{18}\\ \\2)\frac{3}{36}+\frac{8}{36}=\frac{3+8}{36}=\frac{11}{36}\\ \\(\frac{9}{36}-\frac{4}{36})+\frac{7}{36}=\frac{5}{36}+\frac{7}{36}=\frac{1}{3}\\ \\\frac{3}{36}+\frac{8}{36} > (\frac{9}{36}-\frac{4}{36})+\frac{7}{36}$