Question

-23х-6х(5х-41)=259-41х

Answer 1

$\displaystyle -23x-6x(5x-41)=259-41x\\-23x-30x^2+246x=259-41x\\223x-30x^2=259-41x\\223x-30x^2-259+41x=0\\264x-30x^2-259=0\\-30x^2+264x-259=0\\30x^2-264x+259=0\\\\x=\frac{-(-264)б\sqrt{(-264)^2-4*30*259} }{2*30}=\frac{264б\sqrt{69696-31080} }{60}=\\\\\frac{264б\sqrt{38616} }{60}=\frac{264б2\sqrt{9654} }{60}=\frac{132б\sqrt{9654} }{30}$