Question

5х-х2+1=0 решите уравнение

Answer 1

Объяснение:

$5x-x^2+1=0\\x^2-5x-1=0\\D=29\ \ \ \ \sqrt{D}=\sqrt{29} \\x_1=\frac{5-\sqrt{29} }{2} \ \ \ \ \ x_2=\frac{5+\sqrt{29} }{2} .$

Answer 2

$\displaystyle 5x-x^2+1=0\\-x^2+5x+1=0\\\\x=\frac{-5б\sqrt{5^2-4(-1)*1} }{2(-1)}=\frac{-5б\sqrt{5^2-4(-1)} }{2(-1)}=-\frac{-5б\sqrt{25+4} }{2*1}=-\frac{-5б\sqrt{29} }{2}=\frac{5б\sqrt{29} }{2}$