Question

Log1/5(в основании)(3-x)=-3

Answer 1

$\displaystyle\\ \log_{\frac{1}{5} }(3-x) = -3 \\\\3-x=\bigg(\frac{1}{5}\bigg)^{-3} \\ \\3-x = 5^3\\\\3-x=125\\\\-x=122\\\\x=-122$