Question

Решите систему уравнений:
Пожалуйста помогите

Answer 1

Ответ:

Объяснение:

$\left \{ {{12x-2y+3xy-8=0} \atop {y^{2}-6xy-36+9x^{2} =0}} \right. \\\\\left \{ {{12x-2y+3xy=8} \atop {y^{2}-6xy+9x^{2} =36}} \right. \\\\\\\left \{ {{12x-2y+3xy=8} \atop {(y-3x)^{2} =36}} \right. \\\\\\\left \{ {{12x-2y+3xy=8} \atop {y-3x =\sqrt{36} }} \right. \\\\\\\left \{ {{12x-2y+3xy=8} \atop {y-3x =6}} \right. \\y-3x=6\\y=6+3x\\12x-2(6+3x)+3x(6+3x)=8\\12x-12-6x+18x+9x^{2} -8=0\\9x^{2} -24x-20=0\\9x^{2} +6x-30x-20=0\\3x(3x+2)-10(3x+2)=0\\(3x-10)(3x+2)=0\\3x-10=0\\3x=10$

$x_{1}=\frac{10}{3}=3\frac{1}{3} \\3x+2=0\\3x=-2\\x_{2}=-\frac{2}{3}\\y_{1}=6+3x\\y_{1}=6+3*\frac{10}{3} \\y_{1}=6+10=16\\y_{2}=6+3*(-\frac{2}{3} )\\y_{2}=6-2=4$