Question

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 (x + 1)4 − 4(x + 1)2 − 5 = 0​

Answer 1

$\displaystyle\bf\\(x+1)^{4} -4(x+1)^{2} -5=0\\\\(x+1)^{2} =m \ \ , \ \ m\geq 0\\\\m^{2} -4m-5=0\\\\Teorema \ Vieta:\\\\m_{1} +m_{2} =4\\\\m_{1} \cdot m_{2} =-5\\\\m_{1} =5\\\\m_{2} =-1 < 0-neyd\\\\(x+1)^{2} =5\\\\x+1=\pm \ \sqrt{5} \\\\x_{1} =-\sqrt{5} -1\\\\x_{2} =\sqrt{5} -1$