Question

Помогите пожалуйста. Очень срочно

Answer 1

$\displaystyle\bf\\3x+14=4-\frac{8}{x} \\\\\\3x+14-4+\frac{8}{x} =0\\\\\\3x+10+\frac{8}{x} =0\\\\\\\frac{3x\cdot x+10x+8}{x} =0\\\\\\\frac{3x^{2} +10x+8}{x} =0\\\\\\3x^{2} +10x+8=0 \ \ , \ \ x\neq 0\\\\\\D=10^{2} -4\cdot 3\cdot 8=100-96=4=2^{2} \\\\\\x_{1}=\frac{-10-2}{6} =\frac{-12}{6} =-2\\\\\\x_{2} =\frac{-10+2}{6} =-\frac{8}{6} =-1\frac{1}{3} \\\\\\Otvet: \ -2$