Question

АЛГЕБРА СРОЧНО 100 БАЛЛОВ

Answer 1

Решение на фотографии

Answer 2

$\displaystyle\bf\\y=\frac{3}{2+x^{2} } \\\\\\y'=\Big(\frac{3}{2+x^{2} } \Big)'=\frac{3'\cdot(2+x^{2} )-3\cdot(2+x^{2} )'}{(2+x^{2} )^{2} } =\frac{0\cdot(2+x^{2} )-3\cdot 2x}{(2+x^{2} )^{2} } =\\\\\\=\frac{-6x}{(2+x^{2} )^{2} } \\\\\\y'(4)=\frac{-6\cdot 4}{(2+4^{2})^{2} } =\frac{-24}{18^{2} } =-\frac{24}{324} =-\frac{2}{27} \approx-0,07$