Question

помогите пж оценю на 5 звезд​

Answer 1

подставь сам......,..........................

Answer 2

Ответ:

$-\dfrac{1}{12}$

Пошаговое объяснение:

$\dfrac{(a-2b)^{2}}{2(a-6b)}+\dfrac{(a+2b)^{2}}{3(6b-a)}+\dfrac{6ab-b^{2}}{2(a-6b)}=\dfrac{0,5(a^{2}-4ab+4b^{2})}{a-6b}+\dfrac{-\dfrac{1}{3}(a^{2}+4ab+4b^{2})}{a-6b}+$

$+\dfrac{0,5(6ab-b^{2})}{a-6b}=\dfrac{\dfrac{1}{2}a^{2}-\dfrac{1}{3}a^{2}-2ab-\dfrac{4}{3}ab+3ab+2b^{2}-\dfrac{4}{3}b^{2}-\dfrac{1}{2}b^{2}}{a-6b}=$

$=\dfrac{\dfrac{1}{6}a^{2}-\dfrac{1}{3}ab+\dfrac{1}{6}b^{2}}{a-6b}=\dfrac{\dfrac{1}{6}(a^{2}-2ab+b^{2})}{a-6b}=\dfrac{(a-b)^{2}}{6(a-6b)};$

$a=-\dfrac{4}{5}=-0,8 \ , \ b=\dfrac{1}{5}=0,2 \ ;$

$\dfrac{(-0,8-0,2)^{2}}{6(-0,8-6 \cdot 0,2)}=\dfrac{(-1)^{2}}{6(-0,8-1,2)}=\dfrac{1}{6 \cdot (-2)}=-\dfrac{1}{12};$