Question

Хеееелп. Даю дуже багато балів!!!!!!!!!!!!!!!​

Answer 1

Ответ:

Пошаговое объяснение:

$1)(x-8)(2x+2,4)=0\\\\2x^{2} +2,4x-16x-19,2=0\\\\2x^{2} -13,6x-19,2=0\\\\2x^{2} -\frac{68}{5} x-\frac{96}{5} =0\\\\10x^{2} -68x-96=0|2:\\\\5x^{2} -34x-48=0\\\\5x^{2} +6x-40x-48=0\\\\x(5x+6)-8(5x+6)=0\\\\(x-8)(5x+6)=0\\\\x_{1} = 8\\\\x_{2}=-\frac{6}{5}=-1,2$

$2) (x-8)(2x+2,4)=0\\\\x-8=0\\\\2x+2,4=0\\\\x_{1}=8\\\\x_{2}= \frac{-2,4}{2} = -1,2$

$\frac{x}{3}+\frac{x}{12}=\frac{15}{4}\\ \\ x*4+x=15*3\\\\ 5x=45\\\\x=45/5\\\\x=9$

Answer 2

Ответ:

9; -1,2

Пошаговое объяснение:

$\frac{x}{3} +\frac{x}{12} =\frac{15}{4}\\ \\4x+x=45\\5x=45\\x=9$

$(x-8)(2x+2,4)=0\\x-8=0\\x_{1}=8\\2x+2,4=0\\x_{2}=-1,2$