Question

1) x⁴–2x²–8=0
3) x³–4x²–5x=0
4) x+3√x–18=0
5) (x+1)⁴-2(x+1)²-3=0

Answer 1

Відповідь:

1) x = ±2

3)x1 = -1, x2 = 0, x3 = 5.

4) x = 9

5) x1 = -√3-1, x2 = √3-1

Пояснення:

1)

$x^{4}-2x^{2}-8=0$

t²-2t-8

3)

x³-4x²-5x=0

x(x²-4x-5)=0

{x=0

{x+1=0

{x-5=0

4)

x+3√x-18=0

9x-324+36x-x²=0

9(x-36)-x(-36+x)=0

(x-36)(9-x)=0

{36+3√36-18=0

{9+3√9-18=0

{x≠36

{x=9

5)

$(x+1)^4-2(x+1)^2-3=0$

t²-2t-3=0

{t=-1

{t=3

x1 = -√3-1, x2 = √3-1