Question

1) x²+2x–3;
2)–2x²+3x+2.

Answer 1

$\displaystyle 1)x^2+2x-3=x^2+3x-x-3=x(x+3)-(x+3)=(x+3)(x-1)\\\\2)-2x^2+3x+2=-2x^2+4x-x+2=-2x(x-2)-(x-2)=-(x-2)(2x+1)$