Question

Помогите решить
7х²-28=0
5х²-7х=0

Answer 1

$\displaystyle 1)7x^2-28=0\\x^2-4=0\\x^2=4\\x=б2\\\\2)5x^2-7x=0\\x(5x-7)=0\\x=0,5x-7=0\\\\x_1=0,x_2=\frac{7}{5}=1,4$