Question

даю 50 баллов плз помогите пожалуйста​

Answer 1

$\displaystyle\bf\\11x^{2} +44x-(x+4)=0\\\\11x^{2} +44x-x-4=0\\\\11x^{2} +43x-4=0\\\\D=43^{2} -4\cdot 11\cdot (-4)=1849+176=2025=45^{2} \\\\\\x_{1} =\frac{-43-45}{22} =\frac{-88}{22} =-4\\\\\\x_{2} =\frac{-43+45}{22} =\frac{2}{22} =\frac{1}{11} \\\\\\x_{1} =\boxed{-4}\\\\\\x_{2} =\boxed{\frac{1}{11} }$