Question

решить уравнение СРОЧНО

Answer 1

$\displaystyle 1)\frac{5-2y}{8y}+\frac{2y-5}{10y}=0,y\neq 0\\ \\\frac{5(5-2y)+4(2y-5)}{40y}=0\\ \\\frac{25-10y+8y-20}{40y}=0\\ \\\frac{5-2y}{40y}=0\\ \\5-2y=0\\ -2y=-5\\\\y=\frac{5}{2}=2\frac{1}{2}=2,5\\ \\2)1-\frac{1-x}{x}=\frac{2x+2}{x-1},x\neq 0,x\neq 1\\ \\-\frac{1-x}{x}-\frac{2x+2}{x-1}=-1\\ \\-\frac{(x-1)(1-x)+x(2x+2)}{x(x-1)}=-1\\ \\-\frac{(x-1)(-(x-1))+2x^2+2x}{x(x-1)}=-1\\ \\-\frac{-x^2+2x-1+2x^2+2x}{x(x-1)}=-1\\ \\x^2+4x-1=x^2-x\\4x-1=-x\\4x+x=1\\5x=1\\\\x=\frac{1}{5}=0,2$