Question

Срочно!!!Помогите!!!!!!!!!!!!!!!!!!!!!​

Answer 1

$\displaystyle\bf\\\frac{x+9y}{14xy} -\frac{3x+2y^{3} }{xy^{3} } =\frac{(x+9y)\cdot y^{2}-(3x+2y^{3} )\cdot 14 }{14xy^{3} } =\\\\\\=\frac{xy^{2}+9y^{3} -42x-28y^{3} }{14xy^{3} } =\frac{xy^{2} -19y^{3} -42x}{14xy^{3} } \\\\\\Otvet:\\\\\frac{x+9y}{14xy} -\frac{3x+2y^{3} }{xy^{3} } =\frac{xy^{2} -19y^{3} -42x}{14xy^{3} } \\\\\\A=xy^{2} -19y^{3} -42x\\\\\\B=14xy^{3}$