Question

вторая часть первую смотрите в моих вопросах 20 баллов​

Answer 1

$y^{2} -\frac{9y-2 }{7} =0\\\frac{7y^{2} }{7} -\frac{9y-2 }{7} =0\\\\7y^{2}-9y+2=0\\D = (-9)^{2}-4*7*2=25\\y_{1} =\frac{9+5}{14}=1\\y_{2} =\frac{9-5}{14}=\frac{2}{7}$

$x^{2}+x-a=0, x_{1}=4\\4^{2}+4-a=0\\a=20\\x_{1}+x_{2}=-p\\4+x_{2}=-1\\x_{2}=-5$

$x_{1} = -5\\x_{2} = 8$

По т. Виета

$x_{1}+x_{2}=-p\\x_{1}x_{2}=q\\p =5-8 =-3\\q =-8*5=-40\\x^{2}-3x-40=0$