Question

ПОМОЖІТЬ ЕКСТРЕННО!!!!

Answer 1

$\displaystyle\bf\\x=16 \ \ ; \ \ y=-7\\\\\\\left \{ {{ax+3y=11} \atop {5x+2y=12}} \right. \\\\\\16a+3\cdot(-7)=11\\\\16a-21=11\\\\16a=32\\\\\boxed{a=2}\\\\\\\left \{ {{2x+3y=11} | \cdot(-2)\atop {5x+2y=12}|\cdot 3} \right. \\\\\\+\left \{ {{-4x-6y=-22} \atop {15x+6y=36}} \right. \\-----------\\11x=14\\\\x=1\frac{3}{11} \\\\2y=12-5x=12-5\cdot \frac{14}{11} =12-6\frac{4}{11} =5\frac{7}{11} \\\\\\y=5\frac{7}{11} :2=\frac{62}{11} \cdot\frac{1}{2} =\frac{31}{11} =2\frac{9}{11}$

$\displaystyle\bf\\Otvet : \ a=2 \ \ ; \ \ \Big(1\frac{3}{11} \ \ ; \ \ 2\frac{9}{11} \Big)$