Question

Срочно решить нужно
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Answer 1

$\displaystyle\bf\\x^{2} +5x-16=0\\\\Teorema \ Vieta:\\\\x_{1}+x_{2} =-5\\\\x_{1} \cdot x_{2} =-16\\\\\\\frac{x_{2} }{x_{1} } +\frac{x_{1} }{x_{2} } =\frac{x_{1} ^{2} +x_{2} x^{2} }{x_{1} \cdot x_{2} } =\frac{(x_{1} +x_{2} )^{2}-2x_{1} x_{2} }{x_{1}\cdot x _{2} } =\frac{(-5)^{2} -2\cdot(-16)}{-16} =\\\\\\=\frac{25+32}{-16} =-\frac{57}{16} =-3,5625$