Question

Помогите пожалуйста, сложение вычитание дробей с одинаковыми знаменателями нужно провести в общему​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

1)

$\frac{3}{ {a}^{2} + a} + \frac{5a}{ab + b} = \frac{3}{a(a + 1)} + \frac{5a}{b(a + 1)} = \frac{3b}{ab(a + 1)} + \frac{5 {a}^{2} }{ab(a + 1)} = \frac{3b + 5 {a}^{2} }{ {a}^{2}b + ab }$

2)

$\frac{5b}{ax + ay} - \frac{2a}{bx + by} = \frac{5b}{a(x + y)} - \frac{2a}{b(x + y)} = \frac{5 {b}^{2} }{ab(x + y)} - \frac{2 {a}^{2} }{ab(x + y)} = \frac{5 {b}^{2} - 2 {a}^{2} }{abx + aby}$

3)

$\frac{y + a}{ {b}^{2} + ba} + \frac{y - b}{ab + {a}^{2} } = \frac{y + a}{b(b + a)} + \frac{y - b}{a(b + a)} = \frac{ay + {a}^{2} }{ab(b + a)} + \frac{by - {b}^{2} }{ab(b + a)} = \frac{ay + {a}^{2} + by - {b}^{2} }{ab(b + a)} = \\ \\ = \frac{y(a + b) + (a - b)(a + b)}{ab(b + a)} = \frac{(y + a - b)(a + b)}{ab(b + a)} = \frac{y + a - b}{ab}$

4)

$\frac{y - b}{ {a}^{2} - ab} - \frac{y - a}{ab - {b}^{2} } = \frac{y - b}{a(a - b)} - \frac{y - a}{b(a - b)} = \frac{yb - {b}^{2} }{ab(a - b)} - \frac{ya - {a}^{2} }{ab(a - b)} = \frac{yb - {b}^{2} - ya + {a}^{2} }{ab(a - b)} = \\ \\ = \frac{y(b - a) + (a - b)(a + b)}{ab(a - b)} = \frac{ - y(a - b) + (a - b)(a + b)}{ab(a - b)} = \frac{ (- y + a + b)(a - b)}{ab(a - b)} = \frac{ - y + a + b}{ab}$