Question

Алгебра 7 класс, пожалуйста срочно

Answer 1

1.

$6ab + 22 {b}^{2} = 2b(3a + 11b)$

2.

$5yb + 100b - 160d - 8yd = 5b(y + 20) - 8d(20 + y) = (5b - 8d)(y + 20)$

3.

${n}^{5} - 72 - 8{n}^{3} + 9 {n}^{2} = {n}^{3} ( {n}^{2} - 8) + 9( {n}^{2} - 8) = ( {n}^{3} + 9)( {n}^{2} - 8)$

4.

$4d(5d - 6) - 13(5d - 6) = (4d - 13)(5d - 6)$

5.

$- 6m {x}^{3} + 18 {m}^{2} {x}^{2} - 96 {m}^{2} x = - 6mx( {x}^{2} - 3mx + 16m)$

6.

$40 {n}^{2} + 140 + 7 {n}^{5} + 2 {n}^{7} = 20( 2{n}^{2} + 7) + {n}^{5} (2 {n}^{2} + 7) = \\ \\ = (20 + {n}^{5} )(2 {n}^{2} + 7)$

7.

$2 {a}^{9} + {a}^{12} = {a}^{9} (2 + {a}^{3} )$

8.

$xz - 20xd - 18z + 360d = x(z - 20d) - 18(z - 20d) = (x - 18)(z - 20d)$

9.

$18 {d}^{3} {m}^{2} + 6 {d}^{4} m + 84 {d}^{2} {m}^{3} = 6 {d}^{2} m(3dm + {d}^{2} + 14 {m}^{2} )$

10.

$a(4c - 11) - 18(11 - 4c) = a(4c - 11) + 18(4c - 11) = (a + 18)(4c - 11)$