Question

Номер: (2). На фото...​

Answer 1

Ответ:

На фото ответ с решением.

Answer 2

$\displaystyle\bf\\\left \{ {{5x+y=4} \atop {x=3+2y}} \right. \\\\\\\left \{ {{5x+y=4}\ |\cdot2 \ \atop {x-2y=3}} \right. \\\\\\+\left \{ {{10x+2y=8} \atop {x-2y=3}} \right. \\---------\\11x=11\\\\x=1\\\\y=4-5x=4-5\cdot 1=4-5=-1\\\\Otvet: \ \Big(1 \ ; \ -1\Big)$