Question

Помогите срочно решите хотя бы 3 номера

Answer 1

1. ОДЗ: x≠-7
x^2-6x=x-10
x^2-6x-x+10=0
x^2-2x-5x+10=0
x(x-2)-5(x-2)=0
(x-2)(x-5)=0
x-2=0 x-5=0
x1=2 x2=5

2. ОДЗ: x≠-2 x≠0
(x+9)x=(2x-6)(x+2)
(x+9)x-(2x-6)(x+2)=0
x^2+9x-(2x^2+4x-6x-12)=0
x^2+9x-(2x^2-2x-12)=0
x^2+9x-2x^2+2x+12=0
-x^2+11x+12=0
x^2-11x-12=0
x^2+x-12x-12=0
x(x+1)-12(x+1)=0
(x+1)(x-12)=0
x+1=0 x-12=0
x1=-1 x2=12

3. ОДЗ: x≠1
5x^2+9x-5x-9/-(x-1)=0
x(5x+9)-(5x+9)/-(x-1)=0
(5x+9)(x-1)/-(x-1)=0
(5x+9)(-1)=0
-5x-9=0
-5x=9
x=-9/5

4. ОДЗ: x≠-2
18=(4x-6)(x+2)
18-(4x-6)(x+2)=0
18-(4x^2+8x-6x-12)=0
18-(4x^2+2x-12)=0
18-4x^2-2x+12=0
30-4x^2-2x=0
-4x^2-2x+30=0
2x^2+x-15=0
2x^2+6x-5x-15=0
2x(x+3)-5(x+3)=0
(x+3)(2x-5)=0
x+3=0 2x-5=0
x1=-3 x2=5/2

5. ОДЗ: y≠6 y≠0
4/y-6 - 3/y - 16-y/y^2-6y=0
4/y-6 - 3/y - 16-y/y(y-6)=0
4y-3(y-6)-(16-y)/y(y-6)=0
4y-3y+18-16+y/y(y-6)=0
2y+2/y(y-6)=0
2y+2=0
2y=-2
y=-1