Question

даю 20бале
............​

Answer 1

Ответ:

1)

$x1 = 0.x2 = \frac{26}{5}$

2)

$x1 = - 10. x2 = 0$

Answer 2

$\frac{x^{2} -5x}{5} - \frac{x}{25} =0\\\\5(x^{2} -5x)-x=0\\5x^{2} -25x-x=0\\5x^{2} -26x=0\\a=5,b= -26, c=0\\x=\frac{-(-26)+-\sqrt{(-26)^{2}-4*5*0 } }{2*5} \\\\x=\frac{26+-\sqrt{(-26)^{2} } }{10} \\\\x=\frac{26+-26}{10}\\\\x1=0, x2=5.2$

+- это ±

$\frac{x^{2}+5x }{25} +\frac{x}{5}=0\\ \\x^{2} +5x+5x=0\\x^{2} +10x=0\\x(x+10)=0\\x1=-10, x2=0$