Question

СРОЧНООООООООО!!! ДУЖЕ ТРЕБА!!!

Answer 1

Объяснение:

$\frac{3x + 11}{x + 2} - \frac{2x - 9}{x - 4} = 7 \\ \frac{(x - 4) \times (3x + 11) - (x + 2) \times (2x - 9) - 7 \times (x + 2) \times (x - 4)}{(x + 2) \times (x - 4)} = 0 \\ \frac{3 {x}^{2} + 11x - 12x - 44 - 2 {x}^{2} + 9x - 4x + 18 - 7 {x}^{2} + 28x - 14x + 42 }{(x + 2) \times (x - 4)} = 0 \\ \frac{ - 6 {x}^{2} + 18x - 16}{(x + 2) \times (x - 4)} = 0 \\ 6 {x}^{2} - 18x + 16 = 0$

Answer 2

Объяснение:

$\frac{3x+11}{x+2}-\frac{2x-9}{x-4} =7\\(3x+11)*(x-4)-(2x-9)*(x+2)=7*(x+2)*(x-4)\\3x^2-12x+11x-44-(2x^2+4x-9x-18=7*(x^2-4x+2x-8)\\3x^2-x-44-2x^2+5x+18=7x^2-14x-56\\x^2+4x-26=7x^2-14x-56\\6x^2-18x-30=0\ |:6\\x^2-3x-5=0$