Question

Помогите пожалуйста!

Answer 1

$\displaystyle\bf\\3x^{2} -13x+14=0\\\\D=(-13)^{2}-4\cdot 3\cdot 14=169-168=1\\\\\\x_{1} =\frac{13-1}{6} =\frac{12}{6} =2\\\\\\x_{2} =\frac{13+1}{6} =\frac{14}{6} =\frac{7}{3} =2\frac{1}{3} \\\\\\Otvet: \ 2 \ ; \ 2\frac{1}{3}$