Question

1) (х-5)(4х+12)=0
2) |2х-1,2|=2,6


Срочно!!!!​

Answer 1

1) $(x-5)(4x+12)=0$
$x-5 = 0\\4x +12=0\\\\x=5\\x=-3$

2) $|2x-1,2|=2,6$
$2x-1,2=2,6\\2x-1,2=-2,6\\\\x=1,9\\x=-0,7$