Question

Решите неравенства:
1) х2 + 4х + 5 = 0
2) х2 – 12х + 45 <0

Answer 1

х2 + 4х + 5 = 0;

2х + 4х + 5 = 0;

6х+5=0;

6х=-5; (÷6)

$x = - \frac{5}{6}$

х2 – 12х + 45 <0;

2х– 12х + 45 <0;

-10х+45<0;

-10х<-45; (÷(-10))

$x > \frac{9}{2} = x > 4 \frac{1}{2}$