Question

Алгебра, помогите срочно пж

Answer 1

27x^3+27x^2y+9xy^2+y^3

Answer 2

Ответ:

${(3x + y)}^{3} =(3x + y)(9 {x}^{2} + 6xy + {y}^{2} ) = 27 {x}^{3} + 18 {x}^{2} y + 3x {y}^{2} + 9 {x}^{2} y + 6x {y}^{2} + {y}^{3} = 27 {x}^{3} + 27 {x}^{2} y + 9x {y}^{2} + {y}^{3}$