Question

помогите пожалуйста решить ​

Answer 1

$(\frac{11}{3}+\frac{7}{4}) : (\frac{79}{12}-\frac{9}{4})* \frac{4}{5} =(\frac{44}{12}+\frac{21}{12}):(\frac{79}{12}-\frac{27}{12})*\frac{4}{5}=\frac{65}{12}:\frac{52}{12}*\frac{4}{5}=\frac{65}{12}*\frac{12}{52}*\frac{4}{5}=1,25*\frac{4}{5}=\frac{5}{4}*\frac{4}{5}=1$

Answer 2

Ответ:

1

Пошаговое объяснение:

$(\frac{11}{3} +\frac{7}{4} ):(\frac{79}{12} -\frac{9}{4} )*\frac{4}{5} =(\frac{44}{12} +\frac{21}{12} ):(\frac{79}{12} -\frac{27}{12} )*\frac{4}{5} =\frac{65}{12} :\frac{52}{12} *\frac{4}{5} =\frac{65}{12}*\frac{12}{52} *\frac{4}{5} =\frac{65}{52} *\frac{4}{5} =\frac{13}{13} =1$