Question

Решите треугольник АВС, если уголА=79°,АВ=15см и АС=11.​

Answer 1

Объяснение:

si

$sin(79) = 0.981 = 0.98 \\ \frac{ \sin( \alpha ) }{a} = \frac{ \sin( \beta ) }{b} = \frac{ \sin( \gamma ) }{c} \\ \frac{0.98}{15} = \frac{x}{11} \\ x = \frac{0.98 \times 11}{15} = 0.718 \\ \beta = 46 \\ \gamma = 180 - (79 + 46) = 55 \\ \sin(55) = 0.82 \\ \frac{0.72}{11} = \frac{0.82}{x} \\ x = \frac{11 \times 0.82}{0.72} =12.5 \\ otvet \: \ \: \: \beta = 46 \: \: \: \gamma = 55 \: \: \: bc = 12.5$