Question

(х+5)^2+(x-2)^2+(x-7)(x+7)=11x+30

Answer 1

Ответ:

Объяснение:

(x+5)^2+(x-2)^2+(x-7)(x+7)=11x+30

x^2+10x+25+x^2-4x+4+x^2-49=11x+30

3x^2+6x-20-11x-30=0

3x^2-5x-50=0

D=(-5)^2-4*3*(-50)=25+600=625

x=(5±√625)/(2*3)=(5±25)/6

x₁=(5-25)/6=-20/6=-10/3

x₂=(5+25)/6=30/6=5