Question

a^2-13a+22
через дискриминант

Answer 1

Ответ:

$d = b {}^{2} - 4ac = 13^{2} - 4 \times 1 \div 22 = 169 - 88 = 81$

$x1x2 = \frac{ - b + - \sqrt{d} }{2} = \frac{13 + - \sqrt{81} }{2} = \frac{13 + - 9}{2}$

$x1 = \frac{13 + 9}{2} = \frac{22}{2} = 11$

$x2 = \frac{13 - 9}{2} = \frac{4}{2} = 2$