Question

Дам 40 балов!!! Помогите!!! Срочно!!!​

Answer 1

$\displaystyle\bf\\1)\\\\3(x+2)-5x=4-2x\\\\3x+6-5x=4-2x\\\\-2x+2x=4-6\\\\0\cdot x=-2$

корней нет

$\displaystyle\bf\\2)\\\\7x+(5+x)=5+6x\\\\7x+5+x=5+6x\\\\8x-6x=5-5\\\\2x=0\\\\\boxed{\boxed{x=0}}\\\\\\3)\\\\4x+2(x-6)=6(x-2)\\\\4x+2x-12=6x-12\\\\6x-6x=-12+12\\\\0\cdot x=0$

Ответ : любое число

$\displaystyle\bf\\4)\\\\4(2x-1)-3(x-2)=-8\\\\8x-4-3x+6=-8\\\\5x=-8-2\\\\5x=-10\\\\\boxed{\boxed{x=-2}}$