Question

Здравствуйте!Можете пожалуйста помочь с заданием?Буду очень благодарна !
Только столбик А

Answer 1

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}$

$2a(3b + 5) = 6ab + 10a$

$(x + 3)(x + 1) = {x }^{2} +4x+3$

$(b - c)(b + c) = {b}^{2} - {c}^{2}$

${(a - 5)}^{2} = {a}^{2} - 10a + 25$

$(m - n)( {m}^{2} + mn + {n}^{2} ) = {m}^{3} - {n}^{3}$

${(b + 6)}^{2} = {b}^{2} + 12b + 36$

$a(3 {a}^{2} + a) = 3 {a}^{3} + {a}^{2}$

$( {p}^{2} - pq + {q}^{2} )(p + q) = {p}^{3} + {q}^{3}$

$(1 - p)(p + 1) = 1 - {p}^{2}$

$(n - 3)(n - 10) = {n }^{2} - 13n + 30$

$(1 - m)(1 + m + {m}^{2} ) = 1 - {m}^{3}$

$( - a - 4cd)( - d) = ad + 4c {d}^{2}$

$(3m - 2k)(2k + 3m) = 9 {m}^{2} - 4 {k}^{2}$

$( - 3 - x)(x + 1) = - 4x - 3 - {x}^{2}$

${(2a - 7b)}^{2} = 4 {a }^{2} - 28ab + 49 {b}^{2}$

$(2y - 2)(4 - y) = 10y - 2 {y}^{2} - 8$

$2a(3a - 2) = 6 {a}^{2} - 4a$

$(0.1x - 0.9)(0.1x + 0.9) = 0.01 {x}^{2} - 0.81$

${(2x + 0.2y)}^{2} = 4 {x}^{2} + 0.8xy + 0.04 {y}^{2}$

${(2 + k)}^{3} = {k}^{3} + 6 {k}^{2} + 12k + 8$