Question

#8 решите уравнения ю,заранее спасибо)

Answer 1

$1)(x+8 \frac{17}{36} )+7 \frac{31}{36} =25 \frac{1}{36} \\ \\ x=25 \frac{1}{36} -7 \frac{31}{36}-8 \frac{17}{36} \\ \\ \\ 25 \frac{1}{36} -7 \frac{31}{36}-8 \frac{17}{36}=24 \frac{37}{36} -7 \frac{31}{36} -8 \frac{17}{ 36} =17 \frac{6}{36} -8 \frac{17}{36} = \\ \\ =16 \frac{42}{36} -8 \frac{17}{36} =8 \frac{25}{36} \\ \\ x=8 \frac{25}{36}$




$2)12 \frac{13}{45} -(y- \frac{17}{45} )=3 \frac{23}{45} /*45 \\ \\ 598 -45y+17=158 \\ -45y=158-598-17 \\ -45y=457\\y=10 \frac{7}{45}$