Question

помогите пожалуйста ​

Answer 1

${(3a - b)}^{2} = 9 {a}^{2} - 6ab + {b}^{2}$

${(2 + a)}^{3} = {a}^{3} + 6 {a}^{2} + 12a + 8$

${(x - 2)}^{3} = {x}^{3} - 6 {x}^{2} + 12x - 8$

$(3 - a)(9 + 3a + {a}^{2} ) = 27 - {a}^{3}$

${(7y - 1)}^{2} = 49 {y}^{2} - 14y + 1$

${(5c - 9x)}^{2} = 25 {c}^{2} - 90cx + 81 {x}^{2}$

${(x + 3y)}^{3} = {x}^{3} + 9 {x}^{2} y + 27x {y}^{2} + 27 {y}^{3}$

${(2a - b)}^{3} = 8 {a}^{3} - 12 {a}^{2} b + 6a {b}^{2} - {b}^{3}$

${( \frac{1}{3}x - 6) }^{2} = \frac{1}{9} {x}^{2} - 4x + 36$

${(2x - 3y)}^{2} = 4 {x}^{2} - 12xy + 9 {y}^{2}$