Question

Һелп ми плзззззззззз

Answer 1

Ответ:

$\frac{ {c}^{2} + 6c + 9}{c} \div (1 + \frac{3}{c} ) = \frac{(c + 3 {)}^{2} }{c} \div \frac{c + 3}{3} = \frac{(c { + 3)}^{2} }{c} \times \frac{c}{c + 3} = c + 3 \\ \\ c + 3 = 1000 \\ c = 1000 - 3 \\ c = 997$