Question

помогите пожалуйста ❤️​

Answer 1

Ответ:

$(1,5;+\infty);$

$(1; 1,3);$

Объяснение:

$\displaystyle \left \{ {{2x-3 > 0} \atop {7x+4 > 0}} \right. \Leftrightarrow \left \{ {{2x > 3} \atop {7x > -4}} \right. \Leftrightarrow \left \{ {{x > 1,5} \atop {x > -\dfrac{4}{7}}} \right. \Leftrightarrow x > 1,5 \Rightarrow x \in (1,5;+\infty);$

$\displaystyle \left \{ {{3-2x < 1} \atop {1,6+x < 2,9}} \right. \Leftrightarrow \left \{ {{2x-3 > -1} \atop {x < 2,9-1,6}} \right. \Leftrightarrow \left \{ {{2x > 3-1} \atop {x < 1,3}} \right. \Leftrightarrow \left \{ {{2x > 2} \atop {x < 1,3}} \right. \Leftrightarrow \left \{ {{x > 1} \atop {x < 1,3}} \right. \Leftrightarrow$

$\Leftrightarrow x \in (1; 1,3);$