Question

пжпжпж очень срочно!!!!!!!!!!!!

Answer 1

Ответ:

$(2, 0)\\(3, 2)\\(2, 3)$

Объяснение:

$\left \{ {{2x+y=4} \atop {x-3y=2}} \right. \\\\\left \{ {{2x+y=4} \atop {x=2+3y}} \right. \\\\2(2+3y)+y=4 \\4+6y+y=4 \\7y+4=4 \\7y=0 \\y=0\\\\x=2+3y\\x=2+3*0\\x=2+0\\x=2\\\\(2, 0)$

$\left \{ {{3x-2y=5} \atop {x+2y=7}} \right.\\\\\left \{ {{3x-2y=5} \atop {x=7-2y}} \right. \\\\3(7-2y)-2y=5\\21-6y-2y=5\\-8y+21=5\\-8y=-16\\8y=16\\y=2\\\\x=7-2y\\x=7-2*2\\x=7-4\\x=3\\\\(3, 2)$

$\left \{ {{a-4b=-10} \atop {2a+3b=13}} \right. \\\\\left \{ {{a=-10+4b} \atop {2a+3b=13}} \right. \\\\2(-10+4b)+3b=13\\-20+8b+3b=13\\11b-20=13\\11b=33\\b=3\\\\a=-10+4b\\a=-10+4*3\\a=-10+12\\a=2\\\\(2, 3)$