Question

пж помогите алгебра 7 класс

Answer 1

Ответ:

(6-d)²=36-12d+d²

(3m+4n)²=9m²+24mn+16n²

c²+10c+25=(c+5)²

400-40z+z²=(20-z)²

49k²-28k+4=(7k-2)²

(k+m)(m-k)=k²-m²

(1,3x+1,4y⁴)(1,3x-1,4y⁴)=1,69x²-1,96y⁸

m²-k²=(m-k)(m+k)

64-49y²=(8-7y)(8+7y)

0,49a⁶-1,44b²=(0,7a³-1,2b)(0,7a³+1,2b)

Answer 2

(6-d)² = d² - 12d + 36
(3m + 4n)² = 9m² + 24mn + 16n²
c² + 10c + 25 = (c+5)²
400-40z+z² = z² - 40z + 400 = (20-z)²
49k²-28k+4 = (7k-2)²
(k + m)(m - k) = (m+k)(m-k) = m² - k²
(1,3x+1,4y⁴)(1,3x-1,4y⁴) = 1,69x²-1,96y⁸
m²-k² = (m-k)(m+k)
64-49y² = (8-7y)(8+7y)
0,49a⁶-1,44b² = (0,7a³-1,2b)(0,7a³+1,2b)