Предмет: Математика, автор: inzutalzanova9

найдите площадь закрашенной части фигуры.
A) 16
B) 11
C) 36
D) 25​

Приложения:

Ответы

Автор ответа: CosmicTea
0

Ответ:

В) 11π кв.ед.

Пошаговое объяснение:

Площадь четверти окружности равна

(1/4)S₁ = (1/4)πr² = (1/4)12²π = 144π/4 = 36π кв.ед.

Площадь меньшего круга:

S₂ = πr² = π5² = 25π кв.ед.

Площадь закрашенной области равна

(1/4)S₁-S₂ = 36π-25π = 11π кв.ед.

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