Question

Решить уравнения
А) 72х^2-3х=0
Б) х^3 -4х^2 + х-4 = 0

Answer 1

а)

$72x^{2} -3x = 0\\3x(24x-1)=0\\x_{1} = 0\\24x-1 = 0\\x_{2} = \frac{1}{24}$

б)

$x^{3}-4x^{2} +x-4 = 0\\ x^{2} (x-4)+(x-4) = 0\\(x-4)(x^{2} +1) = 0\\x-4 = 0\\x = 4$