Question

11a-7b+21 если 4a-5b+6/5a-4b+6=3​

Answer 1

Объяснение:

$\frac{4a-5b+6}{5a-4b+6}=3\\ 4a-5b+6=3*(5a-4b+6)\\4a-5b+6=15a-12b+18\\11a-7b+12=0\\11a-7b+12+9=0+9\\11a-7b+21=9.$