Question

Разложить на множители

Answer 1

$x^{2} -z^{2} =(x-z)(x+z)\\a^{2} -c^{2} =(a-c)(a+c)\\m^{2}-n^{2} =(m-n)(m+n)\\x^{2} -16=(x-4)(x+4)\\4x^{2} -9z^{2} =(2x-3z)(2x+3z)$

Answer 2

$\displaystyle\bf\\1)\\\\x^{2} - z^{2} =(x-z)(x+z)\\\\2)\\\\a^{2} -c^{2} =(a-c)(a+c)\\\\3)\\\\m^{2} - n^{2} =(m-n)(m+n)\\\\4)\\\\x^{2} -16=x^{2} -4^{2} =(x-4)(x+4)\\\\5)\\\\4x^{2} -9z^{2} =(2x)^{2} -(3z)^{2} =(2x-3z)(2x+3z)$